# SOLUTION: The point (5,y) is five units away from the point (2,70). What are the two possible values of y?

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 Question 598070: The point (5,y) is five units away from the point (2,70). What are the two possible values of y?Answer by math-vortex(472)   (Show Source): You can put this solution on YOUR website!Hi, there-- . Use the distance formula to find the distance between two points. The two different values of y will give you a point above and and a point below (2,70). . The distance formula is . Let (x[1],y[1])=(2,70). Let (x[2],y[2])=(5,y). . Substitute 5 for D and the known values for each point. . Simplify and solve for y. . Square both sides of the equation to clear the square root. . Set the polynomial equal to zero, and factor. . We can use the quadratic formula or the factoring method to solve. 4884 looks like a friendly number to I would try to factor it. If I can't find factors right away, I switch to the quadratic formula. The Q.F. works for every quadratic, but not every quadratic is factorable. . ; We want two factors with a sum of 140, and a product of 4884. I played around with the prime factors and got -2*3*11=-66 and -2*37=-74. So, OR OR . Therefore, the two points are (5,66) and (5,74). . . Check your work for accuracy. Distance between (2,70) and (5,66). . Distance between(2,70) and (5,74). . That's it! Feel free to email via gmail if you have questions about the solution . Ms.Figgy math.in.the.vortex@gmail.com