SOLUTION: how would i find the equation for perpendicular lines (2 of them are intersecting), when one has the points (-1,1),(5,3), and the other (3,-2),(1,4)???

Algebra ->  Algebra  -> Linear-equations -> SOLUTION: how would i find the equation for perpendicular lines (2 of them are intersecting), when one has the points (-1,1),(5,3), and the other (3,-2),(1,4)???      Log On

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 Question 59474This question is from textbook : how would i find the equation for perpendicular lines (2 of them are intersecting), when one has the points (-1,1),(5,3), and the other (3,-2),(1,4)???This question is from textbook Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!(-1,1)(5,3) HAS THE SLOPE OF (3-1)/(5+1)=2/6=1/3 NOW SUBSTITUTING THE 1/3 FOR THE SLOPE WE HAVE Y=mX+b OR Y=1/3X+b NOW REPLACING X & Y WITH ONE SET OF POINTS WE GET 1=1/3(-1)+b 1=-1/3+b b=1-1/3 b=2/3 THUS THE EQUATION FOR THIS LINE IS Y=1/3X+2/3 THE SECOND EQUATION HAS A SLOPE OF (4+2)/(1-3)=6/-2=-3 THUS WE HAVE Y=-3X+b SUBSTITUTING ONE OF THESE POINTS WE GET 3=-3*3+b 3=-9+b b=3+9 b=12 THUS THIS LINE HAS THE EQUATION Y=-3X+12