SOLUTION: Here's what i did: the equation is 2-y=x-6. I'm trying to get it into standard form of a linear equation. I subtracted 6 from both sides and came up with: 8-y=x. I added 8 to bo

Question 58931This question is from textbook
: Here's what i did:
the equation is 2-y=x-6. I'm trying to get it into standard form of a linear equation.
I subtracted 6 from both sides and came up with: 8-y=x.
I added 8 to both sides and got -y=x+8.
Then i subtracted y from both sides and came up with the equation x-y=8. did i do this right? and would the x-intercept be (8,0), and y-intercept (0,-8)?
This question is from textbook

Answer by uma(370) (Show Source): You can put this solution on YOUR website!
You are partly correct.
That is till you arrived at 8-y = x
Adding -8 to both the sides you get,
-y = x - 8
Adding y to both the sides u get,
0 = x-8+y
Or x + y - 8 = 0
U get the intercepts by replacing x and y by 0,
So x intercept would be (8,0) and y intercept would be (0,8)
Good Luck!!!
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