SOLUTION: I'm trying to find how to solve for the following equation. Find the slope/intercept form of a linear equation that is perpendicular to Y=5x and passes through the point (-5,-

Question 58730This question is from textbook Algebra I
: I'm trying to find how to solve for the following equation.
Find the slope/intercept form of a linear equation that is perpendicular to Y=5x and passes through the point (-5,-5). Graph both lines to see that they are perpendicular.
Thank for the help
J.B. Gaskins This question is from textbook Algebra I

Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
Hi J.B. Gaskins
Find the slope/intercept form of a linear equation that is perpendicular to Y=5x and passes through the point (-5,-5). Graph both lines to see that they are perpendicular.
:
Perpendicular lines have slopes that are negative reciprocals of each other, they're opposite signs and upside down.
The line that they gave you is in slope intercept form:, m=slop, (0,b)=y-intercept.
the slope of this line is m=5
The slope of all lines perpendicular to this line is: m=-1/5
Use the point-slope formula to find the perpendicular line going through (x1,y1)=(-5,-5).

The red line is y=5x, the green one is y=(-1/5)x-6. They meet at a 90 degree angle and thus are perpendicular.
Happy Calculating, J.B. Gaskins!!!

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