SOLUTION: Can you please help me solve this problem, thank you. The equation of the line perpendicular to 3x+2y=8 and containing (6,-2) is: Formula: y=mx+b 3x+2y=8 -3x -

Question 585123: Can you please help me solve this problem, thank you.
The equation of the line perpendicular to 3x+2y=8 and containing (6,-2) is:
Formula: y=mx+b
3x+2y=8
-3x -3x
2y=-3x+8
then i divided 2y by 2 and -3x+8 by 2
y=-3/2x+4

then i need to find the x inter or b in y=mx+b
I plug in the coordinates from the equation, (6,-2)
-2=-3/2x(6/1)+b
-2=-18/2+b
-2=-9+b
+9 +9
7=b
The line perpendicular to y=-3/2x+4 is y=-3/2x+7?
The answer i found is y=-3/2x+7
Now I'm not sure if this answer is correct...
Thank you for your help.

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Can you please help me solve this problem, thank you.
The equation of the line perpendicular to 3x+2y=8 and containing (6,-2) is:
Formula: y=mx+b
3x+2y=8
-3x -3x
2y=-3x+8
then i divided 2y by 2 and -3x+8 by 2
y=-3/2x+4
Right here you have to determine the slope of the perpendicular line
the relationship of slopes of perpendicular lines: m1*m2 = -1
m1 =
m2 = slope of perpendicular line
*m2 = -1
m2 = -1 *
m2 = the slope of the perpendicular line
:
Use the point/slope form to find the equation: y - y1 = m(x - x1)
m =
x1 = 6
y2 = -2
y - (-2) = (x - 6)
y + 2 = x - 4
y = x - 4 - 2
y = x - 6; the equation of the perpendicular line
:
Graphically

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