SOLUTION: Think I'm on the right track. d=pz+s. Z is the independent variable. So would it than be d=z+PS? Or would The Equation Look Like d=P+S=Z?

Algebra ->  Linear-equations -> SOLUTION: Think I'm on the right track. d=pz+s. Z is the independent variable. So would it than be d=z+PS? Or would The Equation Look Like d=P+S=Z?      Log On


   



Question 584889: Think I'm on the right track. d=pz+s. Z is the independent variable. So would it than be d=z+PS? Or would The Equation Look Like d=P+S=Z?
Answer by unlockmath(1688) About Me  (Show Source):
You can put this solution on YOUR website!
Hello,
What does the book ask you to solve?
The equations above are incorrect.
RJ