SOLUTION: Think I'm on the right track. d=pz+s. Z is the independent variable. So would it than be d=z+PS? Or would The Equation Look Like d=P+S=Z?

SOLUTION: Think I'm on the right track. d=pz+s. Z is the independent variable. So would it than be d=z+PS? Or would The Equation Look Like d=P+S=Z?

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Question 584889: Think I'm on the right track. d=pz+s. Z is the independent variable. So would it than be d=z+PS? Or would The Equation Look Like d=P+S=Z?
Answer by unlockmath(1688) (Show Source): You can put this solution on YOUR website!
Hello,
What does the book ask you to solve?
The equations above are incorrect.
RJ

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