SOLUTION: Please help me solve this equation: Equation of line passing through (-7,-9) and perpendicular to 8x-9y+2=0 What I've tried: y=-8/9x+2/9 PL: y=9/8x+b EQUALS -9=9/8(-7)+b ??? H

Question 582392: Please help me solve this equation:
Equation of line passing through (-7,-9) and perpendicular to 8x-9y+2=0
What I've tried: y=-8/9x+2/9 PL: y=9/8x+b EQUALS -9=9/8(-7)+b ???
Help please.
Found 2 solutions by josmiceli, KMST:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
In general, if the line is ,
then the line perpendicular to it has a slope

given:

Any line perpendicular to this one has slope

------------------
given that the line passes through (-7,-9 )
Now use the point-slope formula:

Multiply both sides by

Here's a plot of the 2 lines:

Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
--> --> or
The slope of the given line is .
A perpendicular line will have a slope of
Setting up an equation such as and solving for b would work.
--> --> --> -->
Otherwise, the point slope form of the equation is
--> --> --> --> --> -->

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