SOLUTION: how do you write the equation of a line that contains (-4,10)and is parallel to y=2/7x+3?

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Question 57654: how do you write the equation of a line that contains (-4,10)and is parallel to y=2/7x+3?
Answer by funmath(2873) About Me  (Show Source):
You can put this solution on YOUR website!
how do you write the equation of a line that contains (-4,10)and is parallel to y=2/7x+3?
Parallel lines have the same slope.
The equation that they gave you is in slope intercept form:highlight%28y=mx%2Bb%29, where m=slope, and (0,b)=y-intercept.
The slope of the line parallel to y=2/3x+3 is:
y=highlight%282%2F7%29x=3 slope=m=2/7
When you have a point and a slope you can make the equation of the line using the point-slope formula:highlight%28y-y1=m%28x-x1%29%29, where m=slope, and (x1,y1)=given point.
m=2/7, x1=-4, and y1=10
y-10=%282%2F7%29%28x-%28-4%29%29
y-10=%282%2F7%29%28x%2B4%29
7%28y-10%29=7%282%2F7%29%28x%2B4%29
7y-70=2%28x%2B4%29
7y-70=2x%2B8
7y-70%2B70=2x%2B8%2B70
7y=2x%2B78
7y%2F7=2x%2F7%2B78%2F7
y=%282%2F7%29x%2B78%2F7 <---slope intercept form of a line.
Happy Calculating!!!