SOLUTION: what is the equation of the line which is perpendicular to y = -3x + 4 and goes through the point (6, -2)?

Question 576480: what is the equation of the line which is perpendicular to y = -3x + 4 and goes through the point (6, -2)?
Answer by kimberly_16(3) (Show Source): You can put this solution on YOUR website!
The solution to this problem is quite simple :
First,to find the gradient of the line you divide -1 by -3 because the product of the gradient of perpendicular lines is -1.Therefore the gradient of the perpendicular line is 3.
Now just substitute the points (6,-2) into the equation y =3x+ c
You'll get -2 = 3(6)+c
-2 =18+c
-2-18=c
c=-20
therefore eqn. of line perpendicular to y =-3x+4 is y =3x-20
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