SOLUTION: Find an equation of a line passing through (-1,1) and perpendicular to the line whose equation is given by 3x-2y=1.

Question 56642: Find an equation of a line passing through (-1,1) and perpendicular to the line whose equation is given by 3x-2y=1.
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
Find an equation of a line passing through (-1,1) and perpendicular to the line whose equation is given by 3x-2y=1.
First find the slope of the equation by putting it in slope intercept form:, where m=slope and (0,b)=y-intercept:

, the slope,m=3/2.
Perpendicular equations have slopes that are negative reciprocals of each other, so flip the slope over and change its sign.
We need a line with a slope, m=-2/3 going through the point (x1,y1)=(-1,1).
We need to use the point slope formula .

<--Slope intercept form

<--Standard form
Happy Calculating!!!
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