SOLUTION: write an equation that has an x intercept of 3 and is perpendicular to the graph of 5x-3y=2
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Question 565612: write an equation that has an x intercept of 3 and is perpendicular to the graph of 5x-3y=2
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
write an equation that has an x intercept of 3 and is perpendicular to the graph of 5x-3y=2
:
Put the equation in the slope/intercept form to find the slope (y = mx + b)
5x - 3y = 2
- 3y = -5x + 2
Multiply both sides by -1
3y = 5x - 2
divide both sides by 3
y = x -
Slope m1 =
:
The relationship of slope in perpendicular lines is: m1*m2 = -1
Find m2
*m2 = -1
m2 = is the slope of the perpendicular line
:
y = x + b
The x intercept occurs when y = 0, find b
*3 + b = 0
+ b = 0
b =
therefore
y - x + is the equation of the perpendicular line with an x intercept of 3.
:
Graphically
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