SOLUTION: how do i solve (2t-3)^2-4(2t-3)+3=0
Algebra.Com
Question 561998: how do i solve (2t-3)^2-4(2t-3)+3=0
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
factoring ___ [(2t - 3) - 3][(2t - 3) - 1] = 0
(2t - 3) - 3 = 0
(2t - 3) - 1 = 0
RELATED QUESTIONS
How do I solve- 3/2t=... (answered by ReadingBoosters)
-2t^2*2t^3 (answered by chibisan)
Solve. (2t^2+t)^2-4(2t^2+t)+3=0. Let n=(2t^2+t). (answered by stanbon)
how would i solve this equation :... (answered by lynnlo,Alan3354)
how do I solve?
3*5^(2t-1)=75
(answered by Jk22)
How would you solve the following problems:
3(-2-3x)=-9x-4... (answered by WannabeCAgirl83)
How do I solve the equation: 3 tan 2t = √3 in the interval from 0 to... (answered by Alan3354)
t-2(3-2t)=2t+9 (answered by edjones)
t-2(3-2t)=2t+9
3t-6-2t^2+4t=2t+9
7t-6-2t^2=2t+9
5t-6-2t^2=9
5t-2t^2=15
-2t^2+5t-15=0
(answered by edjones)