SOLUTION: find the equation of a line passing through the point (0,4) and perpendicular to the line y=-5x-8?

Question 558794: find the equation of a line passing through the point (0,4) and perpendicular to the line y=-5x-8?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
1 y = -5 x -8
Divide by 1
y = -5 x + -8
Compare this equation with y=mx+b
slope m = -5

The slope of a line perpendicular to the above line will be the negative reciprocal 1/5
m1*m2=-1

m= 1/5 ,point (0,4)
Find b by plugging the values of m & the point in
y=mx+b
4 = 0.00 + b
b= 4
m= 1/5
The required equation is y =( 1/ 5)x+4
m.ananth@hotmail.ca

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