SOLUTION: if your given 1/2 as your slope and 4 as your y-intercep, how would you graph that that in a line?

Question 558013: if your given 1/2 as your slope and 4 as your y-intercep, how would you graph that that in a line?

Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
your graph would look like this:

slope intercept form of the equation for a straight line is y = mx + b
m is the slope
b is the y intercept.
m is equal to (1/2)
b is equal to 4
the equation of the line is:
y = (1/2)x + 4
when x = 0, the value of y is equal to 4.
that's your y intercept.
for all values of x, you apply the equation to get the corresponding value of y.
for the graph of a straight line equation, all you need is 2 points and you draw a straight line between them.
use the y intercept as one of the points.
use any other value of x that would result in an integer value of y (if possible) as your other point.
in this equation, you have:
y = (1/2)x + 4
y will always be (1/2) times the value of x plus 4.
when x is 1, the value of y will be 4 and 1/2.
when x is 2, the value of y will be 5.
use any multiple of x = 2 and the value of y will be an integer.
in this graph, 4 would be a good value for x.
when x = 4, y = (1/2)x + 4 becomes 6
2 points you can use are:
(0,4) and (4,6)
draw a straight line between them and extend the line as far as you want in either direction and you have your graph.
this assumes, of course, that you know how to set up the points on the graph paper.

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