SOLUTION: multiply 4n(3n^8-4n^2-5n+10)

Algebra.Com
Question 553176: multiply 4n(3n^8-4n^2-5n+10)
Found 2 solutions by stanbon, jim_thompson5910:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
multiply 4n(3n^8-4n^2-5n+10)
------------
12n^9 - 15n^3 - 20n^2 + 40n
===============================
Cheers,
Stan H.

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
4n(3n^8-4n^2-5n+10)

4n(3n^8)+4n(-4n^2)+4n(-5n)+4n(10)

12n^9-16n^3-20n^2+40n


So 4n(3n^8-4n^2-5n+10) = 12n^9-16n^3-20n^2+40n

RELATED QUESTIONS

4n(3n^3 - 4n^2 - 5n + 10)multiply can some one help me with... (answered by jim_thompson5910)
Multiply. (5n - 2)(2n^3 - 3n^2 - 4n -... (answered by AAfter Search)
Multiply. (-3n)^2(4n^8)^2 Thank... (answered by checkley77)
1/4n=10=2/3n (answered by Alan3354)
1/4n+10=2/3n (answered by rfer)
5n+3-4n<-5-3n (answered by kayeith)
Please multiply (-4n)^2(3n^7)^2 (answered by checkley77,scottfin)
n^2-4n-3n^2+7n+5n^2 (answered by Fombitz)
-5n-9=4n+2 (answered by robertb)