SOLUTION: I need the derivative of : y = 1 / log x The answer is supposed to be y' = -ln 10 / x(ln x) ^2 I want to know how to do this. Is there a solver on algebra.com to do this?

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Question 550906: I need the derivative of : y = 1 / log x
The answer is supposed to be y' = -ln 10 / x(ln x) ^2
I want to know how to do this.
Is there a solver on algebra.com to do this?
Thank you

Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
y = 

Use the change of base formula:

Y = 

Write as a division:

y = 1÷

Invert and multiply:

y = 1·

y = 

Bring the denominator to the numerator with a -1 power 

y = ln(10)·[ln(x)]-1

                       Now we need two formulas 

                       1)  = 

                       and

                       2)  = ·

y = ln(10)·[ln(x)]-1

 = -1·ln(10)·[ln(x)]-2
 = -ln(10)·
 = -

Edwin

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