SOLUTION: Please graph the following: y= 2/3x +1. Thanks!!!! McGraw Hill 6th edition, Chp. 71. Problem # d.

Algebra ->  Linear-equations -> SOLUTION: Please graph the following: y= 2/3x +1. Thanks!!!! McGraw Hill 6th edition, Chp. 71. Problem # d.      Log On


   

Question 54147: Please graph the following: y= 2/3x +1. Thanks!!!! McGraw Hill 6th edition, Chp. 71. Problem # d.
Found 2 solutions by tiffanyc, funmath:
Answer by tiffanyc(9) About Me  (Show Source):
You can put this solution on YOUR website!
Once again using the form y=mx+b for graphs where m is the slope and b is the y-intercept (where the line crosses the y-axis) Start at the point (0,1) and place your next point up 2 and 3 to the right (3,3). Place next point up 2 and 3 right (5,6), and connect the lines.

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
This is in slope intercept form: highlight%28y=mx%2Bb%29; where highlight%28slope%28m%29=rise%2Frun%29 and highlight%280b=y-intercept%29
y=%282%2F3%29x%2B1
m=2/3 and (0,1) is the y-intercept.
Plot (0,1), from there use your slope (m), go up 2 units(rise) and right 3 units and plot another point. You should be at (3,3) Connect the dots and you have a line!!!
----------------------------------------------
If you haven't been introduced to that method yet.
Let x=0 and solve for y.
y=%282%2F3%29%280%29%2B1
y=0%2B1
y=1
Plot (0,1)
Then let x=3 (I picked 3 because the denominator of the slope is 3 and will cancel)
y=%282%2F3%29%283%29%2B1
y=6%2F3%2B1
y=2%2B1
y=3
Plot (3,3). Connect the dots and you've got a line!
It should look like this no matter which method you chose.
graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C%282%2F3%29x%2B1%29
Happy Calculating!!!