SOLUTION: how do i find the altitude for this problem?, a jetliner covered a horizontal distance of 5 mi. while following a flight path with slope 0.25.how much altitude did it gain?

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I am not sure how you're supposed to be solving this. There are several ways to do it.
Slope corresponds with the tangent of an angle, but we don't have to use that definition unless you're required to right now.
It is also
The run is 5 mi.
We don't know the rise, let rise=y
Slope = .25
Your equation is:



y=1.25 mi
The plane's highth at this time is 1.25 mi at after it has flown a horizontal distance of 5 mi.
Happy Calculating!!!!

You can put this solution on YOUR website!
a jetliner covered a horizontal distance of 5 mi. while following a flight path with slope 0.25.how much altitude did it gain?
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There is a very simple way to do this: One definition of slope is "rise over run". Convert the slope of .25 to the fraction 1/4. That means for every 4 ft horizontally, it rises 1 ft vertically.
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Find the rise (altitude) for a horizontal value of 5 miles.
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=
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Cross mult and you have:
4A = 1*5
A = 5/4
A = 1.25 miles high or 5280*1.25 = 6600 ft is the altitude
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However, I see you are studying Linear equations so they probably want the equation for this: y being the vertical, would be the altitude, the plane will be starting at the origin. (0,0) so the y intercept will be 0
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Using the slope/intercept formula: m = .25, b=0, x = 5
y = mx + b
y = .25x + 0
y = .25(5)
y = 1.25 miles
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you can picture it as a right triangle; the sides are 5 and 1.25 and the hypotenuse is the path of the plane.