SOLUTION: how do you write an equation for the line in slope-intercept form that is parallel to the given line and passes through the given point? y = -2x + 6; (0,1)

Question 538566: how do you write an equation for the line in slope-intercept form that is parallel to the given line and passes through the given point?
y = -2x + 6; (0,1)
Found 3 solutions by stanbon, fcabanski, josmiceli:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
how do you write an equation for the line in slope-intercept form that is parallel to the given line and passes through the given point?
y = -2x + 6; (0,1)
----
All lines parallel to that line must have slope = -2:
You want m = -2 and y = 1 when x = 0
----
y = mx + b
1 = -2*0 + b
b = 1
----
Equation:
y = -2x+1
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Cheers,
Stan H.
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Answer by fcabanski(1391)   (Show Source): You can put this solution on YOUR website!
Slope-intercept form is y=mx+b where m is the slope and b is the y intercept.

The slope of the given line is -2.

The slopes of parallel lines are the same.

So far that makes the line wanted y=-2x+b.

To find the b, substitute the given point into the line. If the point is on the line, then the x and y value of the point work in it's equation, and can be used to find b.

1=2(0)+b

b=1

The equation of this new line is y=-2x+1.

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Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
The given line is in the slope-intercept form
which is: , where = slope,

The slope is , and all line parallel to this
line will also have slope =
So far I have:
Now plug in (x,y) = (0,1) to find

The equation is
Here's a plot of the 2 lines:

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