SOLUTION: Write the slope-intercept equation for the line that passes through (-3, -15) and is perpendicular to -6x + 8y = 3 Please show all of your work.

Question 536615: Write the slope-intercept equation for the line that passes through (-3, -15) and is perpendicular to -6x + 8y = 3 Please show all of your work.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
-6 x + 8 y = 3
Find the slope of this line

8 y = 6 x + 3
Divide by 8
y = 3/4 x + 0.38
Compare this equation with y=mx+b
slope m = 3/4

The slope of a line perpendicular to the above line will be the negative reciprocal -4/3
m1*m2=-1
The slope of the required line will be -1 1/3

m= -4/3 ,point ( -3 , -15 )
Find b by plugging the values of m & the point in
y=mx+b
-15 = 4.00 + b
b= -19
m= -4/3
The required equation is,y =-4/ 3 x -19
m.ananth@hotmail.ca

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