# SOLUTION: How do I use substitution to get the answer x=0 and y=-4 for these problems: 10x+3y= -12 5x+4y= -16 I've tried quite a few times and keep getting fractions. Please help.

Algebra ->  Algebra  -> Linear-equations -> SOLUTION: How do I use substitution to get the answer x=0 and y=-4 for these problems: 10x+3y= -12 5x+4y= -16 I've tried quite a few times and keep getting fractions. Please help.      Log On

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 Click here to see ALL problems on Linear-equations Question 534779: How do I use substitution to get the answer x=0 and y=-4 for these problems: 10x+3y= -12 5x+4y= -16 I've tried quite a few times and keep getting fractions. Please help.Answer by mananth(12270)   (Show Source): You can put this solution on YOUR website!10 x + 3 y = -12 .............1 4 y = -16 -5 x ---------2 / 4 = y = -4 -1.25 x Substitute y in (1) 10x+3(-4-1.25x )= -12 10x-12+ -3.75x = -12 10x-3.75x = -12 12 6.25 x = 0 / 6.25 x= 0 Plug the value of x in (1) 10x+3= -12 10*0+3y = -12 0+3y=-12 3y=-12 / 3 y= -4 m.ananth@hotmail.ca