SOLUTION: find the vertex of the parabola y = -4x2 - 16x - 11

Algebra.Com
Question 530685: find the vertex of the parabola y = -4x2 - 16x - 11
Answer by Earlsdon(6294)   (Show Source): You can put this solution on YOUR website!
The x-coordinate of the vertex can be found by:
where: a = -4 and b = -16.
Evaluate.

Now substitute this value of x into the given quadratic equation to find the value of the y-coordinate.
Evaluate.


The vertex is at (-2,5)
Here's the graph:

RELATED QUESTIONS

find the vertex of the parabola y = 4x2 - 16x -... (answered by oberobic)
Find the vertex of the parabola. y = -4x2 - 16x -... (answered by rfer)
Find the vertex of the parabola.y = -4x2 - 16x -... (answered by stanbon)
find vertex of the parabola y=4x squared - 16x -... (answered by richwmiller)
Find the vertex of the parabola. y = -4x2 - 16x - 11 Possible answers (5,... (answered by Jk22,ewatrrr)
find the vertex of the parabola... (answered by lynnlo)
parabola,x^2 +6x -y +11 =0 find the vertex,focus and directrix of the... (answered by lwsshak3)
what are the vertex and axis of symmetry of the parabola y=x^2... (answered by richwmiller)
what are the vertex and axis of symmetry of the parabola... (answered by ewatrrr)