SOLUTION: find the vertex of the parabola y = 4x2 - 16x - 11

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Question 530679: find the vertex of the parabola y = 4x2 - 16x - 11
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
The axis of symmetry defines the x-coordinate of the vertex.
It is defined by -b/2a.
.
-(-16)/(2*4) = 16/8 = 2
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Substitute x = 2 and find the y value for the vertex.
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y = 4(2^2) -16(2) -11
y = 4*4 -32 -11
y = 16 -43
y = -27
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Vertex is (2,-27).
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+graph%28500%2C500%2C-5%2C10%2C-30%2C30%2C4%2Ax%5E2-16%2Ax-11%29+