SOLUTION: find the vertex of the parabola y = 4x2 - 16x

SOLUTION: find the vertex of the parabola y = 4x2 - 16x - 11

Question 530679: find the vertex of the parabola y = 4x2 - 16x - 11
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
The axis of symmetry defines the x-coordinate of the vertex.
It is defined by -b/2a.
.
-(-16)/(2*4) = 16/8 = 2
.
Substitute x = 2 and find the y value for the vertex.
.
y = 4(2^2) -16(2) -11
y = 4*4 -32 -11
y = 16 -43
y = -27
.
Vertex is (2,-27).
.

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