SOLUTION: 6. Find the x- and y-intercepts for the equation. Please show all of your work. Then graph the equation 2x + 3y = 15

Question 524236: 6. Find the x- and y-intercepts for the equation. Please show all of your work. Then graph the equation 2x + 3y = 15

Found 2 solutions by mananth, Maths68:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
2 x - 3 y = 15
y= - 2/ 3 x -5
Plot the points
x 0 -7.5
y -5 0
(x,y) (0,-5)) (-7.5,0)

Answer by Maths68(1474) (Show Source): You can put this solution on YOUR website!
For y-intercept
===============
2x+3y=15
3y=-2x+15
3y/3=(-2x+15)/3
y=-2x/3 + 15/3
y=-2x/3 + 5
y-intercept = 5

For x-intercept
===============
2x=-3y+15
2x/2=(-3y+15)/2
x=-3y/2+15/2
x-intercept = 15/2

There is another way to find x and y intercepts.
At y-intercept x will be 0 likewise at x-intercept y will be 0
For y-intercept
===============
put x =0
2x + 3y = 15
2(0)+3y=15
3y=15
3y/3=15/3
y=5
y-intercept 5

For x-intercept
===============
put y = 0
2x + 3y = 15
2x + 3(0) = 15
2x=15
x=15/2
x-intercept 15/2
Graph
=====

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