SOLUTION: how do you find the slope-intercept form of an equation?
please help! time is of the essnce! thank you so much.
morgan
Algebra.Com
Question 520420: how do you find the slope-intercept form of an equation?
please help! time is of the essnce! thank you so much.
morgan
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
The slope-intercept form of an equation is:
y = mx + b
.
where
m = slope = change in y / change in x
b = y-intercept, which occurs where x=0, so the ordered pair is (0,b)
.
Consider the following:
2x + 3y = 5
subtract 2x from both sides
3y = -2x +5
divide both sides by 3
y = -(2/3)x + 5/3
.
m = slope = -2/3
.
y-intercept = (0, 5/3)
.
x-intercept occurs where y=0, so simply substitute 0 for y and solve for x.
0 = -(2/3)x + 5/3
add (2/3)x to both sides
(2/3)x = 5/3
multiply both sides by 3 to eliminate fraction
2x = 5
divide both sides by 2
x = 5/2
so the x-intercept is (5/2,0)
.
A graph is often helpful.
.
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