|x/2 - 2| + 1 < 3
|x/2 - 2| < 2
|x/2 - 2| could be positive or negative,
but from the ineqn we understand that it must less than 2.
hence,if positive,it should greater zero,but less than 2.
ie. 0 < x < 2
|x/2 - 2| could be negative,ie.
x/2 - 2 < 0
x/2 < 2
x < 4
our solution would be,
x=]0 2[ U ]+infinity 4[
('U' stands for union)
hence x=]0 2[
You dint mention which set it should fall in,Whole or Real or something else.
Either way,its solution seems to be
x=]0 2[