SOLUTION: find the slope of the line that contains the points:P1 (-4,10) and P2 (6,-10)?
i got the answer
-10-10 over -6-4= 0 over 10 =0
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Question 504083: find the slope of the line that contains the points:P1 (-4,10) and P2 (6,-10)?
i got the answer
-10-10 over -6-4= 0 over 10 =0
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
P1 = (-4,10)
P2 = (6,-10)
.
slope = change in y / change in x
.
change in y = -10 -10 = -20
change in x = 6 -(-4) = 10
.
slope = -20/10 = -2
.
y = -2x + b
.
We can substitute one of the known points to find 'b'.
Use P1, (-4,10)
.
10 = -2(-4) + b
10 = 8 + b
b = 2
.
y = -2x +2
.
We can check this solution using the other point, P2 = (6,-10).
y = -2x + 2
y = -2(6) + 2
y = -12+2
y =10
OK
.
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