SOLUTION: I have 2 questions and if someone could help i would really appreciate it!!
1) 1/7(2x-5)=3/8x-5/7
2) 5/6(x-2)=x-3
If it helps i am a college student using the textbook "
Algebra.Com
Question 502886: I have 2 questions and if someone could help i would really appreciate it!!
1) 1/7(2x-5)=3/8x-5/7
2) 5/6(x-2)=x-3
If it helps i am a college student using the textbook "Elementary Algebra For College Students" (8th edition) and i am learning about Solving Linear Equations and Inequalities i believe.
Thank you so much!!
Found 2 solutions by stanbon, jim_thompson5910:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
1) (1/7)(2x-5)=(3/8)x-(5/7)
Multiply both sides by 56 to get:
8(2x-5) = 7*3 - 8*5
------
16x-40 = 21-40
16x = 21
x = 21/16
---------------------
2) (5/6)(x-2)=x-3
Multiply both sides by 6 to get:
5(x-2) = 6x-18
5x-10 = 6x-18
x = 8
--------------
Cheers,
Stan H.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
I'll do the first one to get you started.
1)
Start with the given equation.
Distribute.
Multiply.
Now multiply EVERY term by the LCD 56 to clear out the fractions.
Multiply.
Add to both sides.
Subtract from both sides.
Combine like terms on the left side.
Combine like terms on the right side.
Divide both sides by to isolate .
Reduce.
So the solution is
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