SOLUTION: SOLVE: parallel to 2y+x=3; through (3,-2)

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Question 500001: SOLVE:
parallel to 2y+x=3; through (3,-2)

Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
2y +x = 3
subtract x from both sides
2y = -x +3
divide both sides by 2
y = -x/2 +3/2
or
y = -(1/2)x + 3/2
.
So, a line parallel to this line will have a slope, 'm', = -1/2, too.
.
y = (-1/2)x + b
.
To find 'b' you use the point it has to go through: (3, -2)
.
So, when x=3, y=-2. Substitute these values to find 'b'.
.
-2 = (-1/2)(3) + b
-2 = -3/2 + b
Add 3/2 to both sides
-2 + 3/2 = b
b = -1/2
.
That makes the equation:
y = -(1/2)x -(1/2)
.
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