SOLUTION: a line perpendicular to -8x-4y=10 and having the same y intercept as 1/2x-1/4y=-2

Question 499937: a line perpendicular to -8x-4y=10 and having the same y intercept as 1/2x-1/4y=-2
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
-8x -4y = 10
-4y = 8x +10
y = -2x - 5/2
.
1/2x -1/4y = -2
-1/4y = -1/2x -2
multiply both sides by -4
y = 2x +8
.
A line perpendicular to the first equation will have a slope of 1/2 (the inverse reciprocal of -2).
The required y-intercept is 8, taken from the second equation.
.
y = 1/2x +8
.
In the following graph, the first equation is red; the second is green; and the final equation is blue.

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