SOLUTION: How do I find intercepts for the graph of the equation given: x+6y=0

Question 486885: How do I find intercepts for the graph of the equation given:
x+6y=0
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
the y intercept is the value of y when x is equal to 0.
the x intercept is the value of x when y is equal to 0.

your equation is x + 6y = 0

when x is equal to 0, the value of y is equal to 0.
when y is equal to 0, the value of x is equal to 0.
your x and y intercepts are both equal to 0.

the graph of the equation goes through the origin.

here's what your graph looks like.

to graph this equation, you needed to solve for y.

you start with x + 6y = 0
subtract x from both sides of the equation to get 6y = -x
divide both sides of the equation by 6 to get y = -x/6

when you solved for y, you converted the equation from standard form of ax + by = c to slope intercept form of y = mx + b.

m is the slope and b is the y intercept.

your slope is -(1/6)
your y intercept is 0.

to find the x intercept when the equation is in this form, simply set y = 0 and solve for x.

y = -(1/6)x becomes 0 = -(1/6)x.
divide both sides of this equation by -(1/6) to get 0 = x.

you wind up with the same answer regardless of the form the equation is in to start with.

x intercept = 0
t intercept = 0

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