SOLUTION: (x+7)(x-1)=(x+1)^2
i got to this step: X^2-x+7x-(x+1)^2+7=0
I do not uderstand what to do after the exponent is confusing me and i will really apreciate your help/advice thank
Algebra.Com
Question 486233: (x+7)(x-1)=(x+1)^2
i got to this step: X^2-x+7x-(x+1)^2+7=0
I do not uderstand what to do after the exponent is confusing me and i will really apreciate your help/advice thank you in adcanced.
Found 2 solutions by mananth, chessace:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
you should expand the brackets
re arrange the terms
4x-8=0
4x=8
x=2
Answer by chessace(471) (Show Source): You can put this solution on YOUR website!
First off, you got the final sign wrong, it's -7.
You need to expand the (x+1)^2 and collect terms:
x^2 +6x -(x^2 + 2x + 1) -7 = 0
Collect terms again (you do it too):
4x - 8 = 0
More little steps for you results in:
x = 2
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