SOLUTION: Instructions say: "Find an equation in standard form for the line described." The question is: "Through P (5, -2) and perpendicular to the line 2x-3y=6. Please help!!!

Question 480714: Instructions say: "Find an equation in standard form for the line described." The question is: "Through P (5, -2) and perpendicular to the line 2x-3y=6. Please help!!!
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
"Find an equation in standard form for the line described." The question is: "Through P (5, -2) and perpendicular to the line 2x-3y=6.
**
Standard form of equation for a straight line:
y=mx+b, m=slope and b=y-intercept
..
rewrite given equation
2x-3y=6
3y=2x-6
slope=2
..
Perpendicular line:
slope=negative reciprocal of slope of given equation=-1/2
equation: y=(-1/2)x+b
solving for b using coordinates of given point (5, -2) thru which line passes.
-2=-5/2+b
b=-2+5/2=-4/2+5/2=1/2
Equation: y=x/2+1/2
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