SOLUTION: What is the equation of a line that passes through (1, 8) and (2, -4)?

Question 479498: What is the equation of a line that passes through (1, 8) and (2, -4)?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
x1 y1 x2 y2
1 8 2 -4

slope m = (y2-y1)/(x2-x1)
( -4 - 8 )/( 2 - 1 )
( -12 / 1 )
m= -12.00 -12

Plug value of the slope and point ( 1 , 8 ) in
Y = m x + b
8.00 = -12 + b
b= 8 -12
b= 20
So the equation will be
Y = -12 x + 20
m.ananth@hotmail.ca

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