# SOLUTION: What is the equation "in slope-intercept form" of the line perpindicular to the segment between (1,3) and (5,5) and passing through (3,4)

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 Click here to see ALL problems on Linear-equations Question 478306: What is the equation "in slope-intercept form" of the line perpindicular to the segment between (1,3) and (5,5) and passing through (3,4)Answer by lwsshak3(6460)   (Show Source): You can put this solution on YOUR website!What is the equation "in slope-intercept form" of the line perpindicular to the segment between (1,3) and (5,5) and passing through (3,4) ** Standard form for a straight line: y=mx+b, m=slope, b=y-intercept .. Slope of line segment between (1,3) and (5,5)=∆y/∆x=(5-3)/5-1=2/4=1/2 .. Slope of line perpendicular to line segment=-2 (negative reciprocal) Equation of line: y=-2x+b solving for b using given point line passes thru, (3,4) 4=-2*3+b 4=-6+b b=10 Equation: y=-2x+10