SOLUTION: Find an equation of the line containing the given pair of points (-3,-4) and (-8,-1) the equation of hte line in slope-intercept form= y= I get so far on the equation and th

Question 473266: Find an equation of the line containing the given pair of points (-3,-4) and (-8,-1) the equation of hte line in slope-intercept form=
y=
I get so far on the equation and then get lost somehow at the end I cannot get it right!! Please help :)
Found 2 solutions by stanbon, jim_thompson5910:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find an equation of the line containing the given pair of points
(-3,-4) and (-8,-1)
---------------
slope = (-1--4)/(-8--3) = 3/-5 = -3/5
------------------
Form: y = mx + b
---
Substitute for y,x,m and solve for "b":
---
-1 = (-3/5)*-8 + b
-1 = (24/5) + b
-(5/5) = (24/5) + b
b = -(29/5)
--------------------
Equation:
y = (-3/5)x - (29/5)
==========================
Cheers,
Stan H.
=============
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

First let's find the slope of the line through the points and

Note: is the first point . So this means that and .
Also, is the second point . So this means that and .

Start with the slope formula.

Plug in , , , and

Subtract from to get

Subtract from to get

Reduce

So the slope of the line that goes through the points and is

Now let's use the point slope formula:

Start with the point slope formula

Plug in , , and

Rewrite as

Rewrite as

Distribute

Multiply

Subtract 4 from both sides.

Combine like terms. note: If you need help with fractions, check out this solver.

So the equation that goes through the points and is

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