SOLUTION: Please help me with this algebra problem. find the x and y intercepts -2x + 5y = 15
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Question 467427: Please help me with this algebra problem. find the x and y intercepts -2x + 5y = 15
Found 2 solutions by jim_thompson5910, algebrahouse.com:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
x-intercept
To find the x-intercept, plug in and solve for x
Start with the given equation.
Plug in .
Multiply and 0 to get 0.
Simplify.
Divide both sides by to isolate .
Reduce.
So the x-intercept is )
.
------------------------------------------
y-intercept
To find the y-intercept, plug in and solve for y
Start with the given equation.
Plug in .
Multiply and 0 to get 0.
Simplify.
Divide both sides by to isolate .
Reduce.
So the y-intercept is )
.
Answer by algebrahouse.com(1659) (Show Source): You can put this solution on YOUR website!
-2x + 5y = 15
At the x-intercept (where the line crosses the x-axis), y is 0.
To find the x-intercept, substitute 0 in for y:
-2x + 5y = 15
-2x + 5(0) = 15 {substituted 0 in for y}
-2x = 15 {multiplied 5 by 0}
x = -15/2 {divided both sides by -2}
x-intercept is -15/2.....the coordinates are (-15/2,0)
At the y-intercept (where the line crosses the y-axis), x is 0.
To find the y-intercept, substitute 0 in for x}
-2x + 5y = 15
-2(0) + 5y = 15 {substituted 0 in for x}
5y = 15 {multiplied -2 by 0}
y = 3 {divided both sides by 5}
y-intercept is 3.....the coordinates are (0,3)
For more help from me, visit: www.algebrahouse.com
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