SOLUTION: 1. through (-7,2) and parallel to 3x+5y=6 2. through (-7,2) and perpendicular to y=2x 3. find x- and y- and graph: y=5 4. In 1980, there were 119,000 farms in Iowa. As of 2005,

SOLUTION: 1. through (-7,2) and parallel to 3x+5y=6 2. through (-7,2) and perpendicular to y=2x 3. find x- and y- and graph: y=5 4. In 1980, there were 119,000 farms in Iowa. As of 2005,

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