SOLUTION: A dehydrated patient needs a 2.6% saline IV. Unfortunately, the hospital only has bags of 8% and 2% saline solutions. How many liters of each of these solutions should be mixed tog

Question 465995: A dehydrated patient needs a 2.6% saline IV. Unfortunately, the hospital only has bags of 8% and 2% saline solutions. How many liters of each of these solutions should be mixed together to yield 2 liters of the desired concentration?
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
A dehydrated patient needs a 2.6% saline IV. Unfortunately, the hospital only has bags of 8% and 2% saline solutions. How many liters of each of these solutions should be mixed together to yield 2 liters of the desired concentration?
.
Let x = amount (liters) of 8%
then
2-x = amount (liters) of 2%
.
.08x + .02(2-x) = .026(2)
.08x + .04-.02x = .052
.06x + .04 = .052
.06x = .012
x = 0.2 liters (of 8%)
.
Amount ot 2%:
2-x = 2-0.2 = 1.8 liters

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