SOLUTION: What is the equation of a line which contains the points (-3,4) and (6,-2)?
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Question 465371: What is the equation of a line which contains the points (-3,4) and (6,-2)?
Answer by rfer(16322) (Show Source): You can put this solution on YOUR website!
m=(-2-4)/(6--3)
m=-6/9
m=-2/3
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y=mx+b
4=-2/3*-3+b
4=2+b
b=2
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y=-2/3x+2
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