SOLUTION: how do you solve the system? 5x- 1y=8 and 25x- 5y= 32
Algebra.Com
Question 455943: how do you solve the system? 5x- 1y=8 and 25x- 5y= 32
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
how do you solve the system? 5x- 1y=8 and 25x- 5y= 32
..
5x- 1y=8
y=5x-8
..
25x- 5y= 32
sub for y
25x-5(5x-8)=32
25x-25x+40=32
40≠32 (no solution)
..
The reason there is no solution is that the lines of given linear equations are parallel to each other, there is no point of intersection. Equations are independent and system is inconsistent.
RELATED QUESTIONS
5x + 3y = -10
3x + 5y= -6
how do you solve the system of equations by... (answered by persian52)
Please solve and graph the following system:
3x-5y = - 9
5x-6y = -8
Thank... (answered by mananth)
Tell how many solutions the system has. do not actually solve.
5x+4y=-1... (answered by bucky)
can you tell me how to solve the linear system for:
5x+6y=3... (answered by Gogonati,Edwin McCravy)
how do I solve this system of equations by substitution
5x+6y=32... (answered by Edwin McCravy)
How do you solve this problem?
assuming x>0 and y>0, if 16y^2+40xy+25x^2=36, what is... (answered by lwsshak3)
Write a system of linear equations in two variables
5x+5y = 10
5x-5y = 0
how do... (answered by Alan3354)
How do you solve the system -4x-6y=-12 and y=5x+19 using... (answered by ewatrrr)
How do you solve the equation:... (answered by stanbon)