SOLUTION: factor the following terms:
y^2-16/25
Algebra.Com
Question 450571: factor the following terms:
y^2-16/25
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
y^2-16/25
can be written as:
y^2 - (4/5)^2
notice that it is now a "difference of squares" (special factor case):
(y - 4/5)(y + 4/5)
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