SOLUTION: graph the line that goes through point (3,8) and is parallel to the line whose equation is 6y-10x=30

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Question 448805: graph the line that goes through point (3,8) and is parallel to the line whose equation is 6y-10x=30
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
(3,8) and is parallel to the line whose equation is 6y-10x=30
-10x+6y=30
Find the slope of this line
y=10x+30
Divide by 6
y=1.67x +5
Compare this equation with y=mx+b
slope m = 1.67
The slope of a line parallel to the above line will be the same
The slope of the required line will be 1.67
m= 1.67 ,point (3,8)
Find b by plugging the values of m & the point in
y=mx+b
8=5.00+b
b=3
m=1.67
Plug value of the slope and b
The required equation is y=1.67 x+3
...
y=1.67 x+3
when x= 0 y= 3 ( 0 , 3 )
when y = 0 x= -1.8 ( -1.8 , 0 )



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