SOLUTION: A rectangle is 3 feet longer than it is wide, and its area is 40 square feet. Find its dimensions.
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Question 44861This question is from textbook INTERMEDIATE ALGEBRA
: A rectangle is 3 feet longer than it is wide, and its area is 40 square feet. Find its dimensions.
This question is from textbook INTERMEDIATE ALGEBRA
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
X*(X+3)=40 OR X~2+3X-40=0 OR (X+8)(X-5)=0 OR X=-8 & X=5 THEN X+3=8
PROOF 5*8=40 THUS THE DIMENTIONS ARE 5 BY 8 FEET
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