SOLUTION: 2zx^2y=18 where x=1, z=y please help me solve this equation

SOLUTION: 2zx^2y=18 where x=1, z=y please help me solve this equation

Algebra.Com

Question 446565: 2zx^2y=18 where x=1, z=y
please help me solve this equation
Answer by sudhanshu_kmr(1152) (Show Source): You can put this solution on YOUR website!

x=1, z = y = -3
or
z = y = 3

RELATED QUESTIONS
Please help me solve this equation: {{{ x^2-y^2+2zx+2yz+2y-2z-1... (answered by Alan3354)

I have a test at my college on monday and I was wondering if you could please explain to... (answered by elima)

2zx^2y=18 x=1... (answered by rapaljer)

How can I solve this?! Please help me! The answer is 0 (x^2yz)/((x-y)(x-z))... (answered by Alan3354)

Can you help me to solve this? I know that the answer is 0 (x^2yz)/((x-y)(x-z))... (answered by Alan3354)

Can you help me solve this? The answer is 0 I need the process! (x^2yz)/((x-y)(x-z))... (answered by Alan3354)

Please help me solve this equation, solve for y :... (answered by josgarithmetic,MathTherapy)

Please help me to solve this equation: x+y+z=2 -x+2y+3z=2 2x-3y-z=1... (answered by ankor@dixie-net.com)

2zx^2y=18 x=1 z=y how is the answer... (answered by richwmiller)