Hi,

 



Passing through (5,8)and perpendicular to the line with the equation 5x-2y=10

perpendicular to the line with the equation 

5x-2y=10  OR y = (5/2)x - 5   m = (5/2)

Perpendicular lines have slopes that are negative reciprocals on one another

New Line

 y = (-2/5)x + b  |Using ordered pair (5,8) to solve for b

 8 = (-2/5)*5 + b

10 = b

 y = (-2/5)x + 10   OR 2x + 5y = 50

 

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