SOLUTION: How do I solve this problem, Write the slope-intercept form of an equation of the line that passes through the y-axis at 5 and is perpendicular to the graph of 2x=3y+4.

Question 436946: How do I solve this problem,
Write the slope-intercept form of an equation of the line that passes through the y-axis at 5 and is perpendicular to the graph of 2x=3y+4.
Found 2 solutions by MathLover1, ewatrrr:
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!

Your line represented by
the line that passes through the at
it means if , ; and that means

To find the slope of this line perpendicular to , write it in sloe-intercept form first:

the slope is 2/3, and you take the negative reciprocal of the slop of your given line, or -3/2
This gives you a general line of .
now, graph them both:

Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

Hi
line passing through the y-axis at 5 and perpendicular to the graph of 2x=3y+4
Using the standard slope-intercept form for an equation of a line y = mx + b
where m is the slope and b the y-intercept.
2x = 3y+4 OR y = (-2/3)x - 4/3 Slope m = (-2/3)
New Line:
y = (3/2)x + 5 |Slopes of perpendicular lines are negative reciprocals
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