Hi

Using the standard slope-intercept form for an equation of a line y = mx + b

  where m is the slope and b the y-intercept.  

line that is passing through the point of (-2,5) 

and is perpendicular to the equation y=3x+4. slope m = 3/1

perpendicular have slopes that are negative reciproclas of one another:

 New Line

 y = (-1/3)x + b   |Using ordered pair pt(-2,5) to solve for b

 5 = (-1/3)*-2 + b

 13/3 = b

    y = (-1/3)x + 13/3   OR x+ 3y = 13



 

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